WEBVTT

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Hello again let's continue with the operators now and let's complete the bitwise operators the assignment

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operators the membership and the identity operators quickly in this review.

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All right so we go into programming that ASPI to 3 and let's understand.

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I'm not going to make a file and write them in the sialic So this time let's say is equal to 5.

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Or or let me say easy equal to 7 and B is equal to equals 10.

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Now when I see the bit twice operate.

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What you're going to go with this a and b it takes two white right.

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Now we need to understand a because a 7.

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I say it can get it as binary 0 0 0 0 0 1 1 1.

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That's the binary of the 7 cuts the Big 8 bits each.

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And then if I say be that Astin it's going to be written as 0 0 0 0 1 0 1 0.

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All right.

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Now when you do this twice and when you do a bit why isn't that the campus and operable.

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And then it stands.

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Each of these bits twice.

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1 and 0 0 1 and 1 is a 1 so if I write and the it's going to be something like this

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0 0 0 0 1 0 0 0 and 0 0 0 and 1 is 0 1 and 0 0 1 and 1 is 1 and 1 and zero is zero.

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What is this too perfect.

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That's the answer.

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All right let's go on to let's go on to what would be a or OK A or B what would it be.

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All right.

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It's going to be OK.

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I'll just say this.

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Or B before going to a command.

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Sorry that's 15.

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How did that come.

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I'll write this once again and I'll write this B once again and then we will do the oring part of it.

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That is a or b.

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So that's going to be 0 0 0 0 0 0 0 0 1 1 1 or 2 1 is 1 1 or 0 is again 1 0 or 1.

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If any one of them on one or at least one of them one.

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OK.

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And to now.

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So we got a or b then you have another operator called as a exhaust.

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Now what is exhaust.

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Again if I copied these two things out to

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a zombie that's going to be given as exactly 0 0 0 0 0 0 0 0 eggs or UPS.

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Just a minute one sec x or x or is one exhorter is one.

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Yeah.

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When any one of them are one.

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So if it pulls them or zeros or both of them or once it's going to be answered it's going to be zero

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so $0.00 exhaust below zero zero zero zero or one at least one of them is one.

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Yes.

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Then it is going to be 1 1 exhorter zero is again one but one in Zone One is 0 1 0 0 is 1 again.

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What is that.

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This is 13.

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This is a plus for that astraddle 12 plus one that is Kirti OK.

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We now go on to the next bitwise operator that is knocked off.

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It says it's mine is it.

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OK what is not ofI and that's mynahs.

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OK.

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So if it's a copy the when you put it up here.

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Not or not they are negative off the negation of the.

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There's going to be given as a complement of each of them.

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So you know this is a negative.

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No.

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Now there's a negative number which is stored in this particular fashion.

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Now if you want to know what kind of number this is you need to get the two complement of the complement

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of this is going to be OK.

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So so this negative number not of the is going to get this and this is going to be exactly the way that

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it's going to be stored in your memory.

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But then if you want to read it why does vinyl see it when you write not of his mindset.

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OK.

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Why is it minus eight then you need to take the two's complement of this and figure out what is the

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positive number of which this is all right.

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So it is a complement.

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So negative numbers are starting to complement form.

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So then I can say this right here.

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If I were to take the compliment.

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I would just say zero.

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First then you take the one complement that is 000.00 1 1 1 and then I need to add 1 to it.

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So if I add a 1 to it one plus one.

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So one plus one to the last bit one if I add to this last bit one to one to the last one what is going

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to happen one plus one is zero.

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Gary one zero carry one.

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This one needs to be added with this one.

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Again it's going to be zero carry one.

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Again this is going to be zero carry one.

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The one is going to come here.

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So this one right here.

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Now what is this number.

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And hence the number that is.

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This particular number is minus eat.

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So this is how you read what is a negative number.

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All right.

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Now we go on to the next one that is so you resaw bitwise operators and or X or negation and then oh

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we have Sorry congressman and then we have the right shift and the left shift.

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OK a right shift by 2 and to it says one by one.

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OK I'll store a I'll write it once again and then let's see what is it right.

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Shift by two OK what is it going to be.

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Each of the bits are going to be shifted to the right by two.

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So this bit is going to be shifted one place you're in one place here.

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So this bit is going to finally come here.

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The first MSBA is going to come here.

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The next bit is also going to be shifted by two which means that it's going to come here.

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The next one is going to come here.

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So these are the three bits which got shifted to the right.

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What about East to deal so we come off of that.

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Then comes the three ones.

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This one is going to be shifted to the right which means that one is going.

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That one is also going to come here.

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But what about the rest of the day once you are gone.

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OK.

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They cannot be shifted to the right because this is the maximum that it can hold.

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What about these Two-Bits.

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These debates are going to be zero.

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And you they just go flat.

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So what's the answer.

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Right shifting the bits by two onset is one.

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All right then we go on to left shifting belts by two.

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OK.

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So that's going to be a left shift by two.

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OK so if I do that I'm going to shift.

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OK.

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Not not this one.

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There's a lot of the shape shifting there's some shifting a by too so they're shifted by two.

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If I shifted or were I'm going to get like this 000 right these two zeroes will go off.

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It is not going to be there then it's going to be 1 1 1 and then zeros are going to be added at the

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end.

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Again this is going to be the answer.

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Now what exactly is that.

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A lecture by two that's going to be 28.

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This is 16 plus 16 plus eight is how much that's going to be.

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Twenty four twenty four plus four is straight.

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And that's right.

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So you are really off shift to that is 28 clear.

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These are the bitwise operators.

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Now we go on to some other operators also.

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So the so that we finish up the operators quickly.

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OK.

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By the way where are these operators going to be used.

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We're going to use them.

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Maybe when you have certain data and you want to hide a few bits you want to show a few bits you want

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to do some operations where you want do you want to do some bitwise operations on that data.

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Okay.

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On any kind of data that you get when you will use any of the bitwise operators.

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Okay another operator which is going to be used very frequently.

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Scholars.

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The assignment operators.

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OK.

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This is nothing.

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This is not is not difficult to understand why.

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Because if I do a class 2 what's the answer 9 but if I say what is the value of it now it is seven.

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Which means which means it has not changed.

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We got the answer A-plus too because we are printing a too.

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But did we when we change D-plus do.

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Did we assign it back to it.

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Did we change it.

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No he was still remaining seven hands you can write that.

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Hence we have an.

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You can actually write something like this a plus do is equal to a plus two.

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Now if I say what is a.

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That's nine.

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That's right.

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But instead of writing this White says will give you an operator.

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It says A what do you want or do you want to add it to.

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And then you could get back to me.

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You can write something like this plus sequel to a plus equals or two.

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And it was Garny nine.

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It has become Levan correct.

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OK.